5p^2+10p-115=0

Solution for 5p^2+10p-115=0 equation:

5p^2+10p-115=0

a = 5; b = 10; c = -115;
Δ = b2-4ac
Δ = 102-4·5·(-115)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-20\sqrt{6}}{2*5}=\frac{-10-20\sqrt{6}}{10}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+20\sqrt{6}}{2*5}=\frac{-10+20\sqrt{6}}{10}
$